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Designing Coupled Inductors

Apr 1, 2006 12:00 PM
By John Gallagher, Field Applications Engineer, Pulse, San Diego



In regards to the reluctance model, the reverse-series measurement is equivalent to putting the two windings in parallel, and the equivalent circuit reduces to that shown in Fig. 3f. It is clear from this figure that the equivalent reluctance is equal to:

Again, knowing that L = N2 / R and using Eqs. 5 and 6 yields:

And using Eq. 8 to solve Eq. 3 yields:

With the definition of LK and LM in terms of R and RC it would be possible now to design a coupled inductor. However, it would not be possible to determine if the inductor was going to saturate in an actual application without first determining the amount of flux in the various sections of the core. To determine this, we need to solve for the flux (Φ1, Φ2 and Φ3) in the reluctance model. The reluctance model (Fig. 3c) resembles the electrical circuit used in Millman's Theorem, and as such this theorem can be used to solve for the flux in each leg:

where I1 and I2 are the currents in phase one and phase two, respectively.

It can be seen that the expression RC / (R2 + 2RRC) in Eqs. 10 and 11 is similar to the definition of LM in Eq. 9, and it should be noted that the expression (R + RC) / (R2 + 2RRC) is similar to adding LM plus LK in Eq. 3. Substitution and noting that LM = p × LK yields:


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