Single Boost Converter Builds Dual Polarity Supply
Sep 1, 2006 12:00 PM
By Yogesh Sharma, Applications Engineer, Standard Power Products Group, Analog Devices, San Jose, Ca
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In Fig. 1, when the divided output voltage presented at FB increases, the control system decreases the inductor current. This maintains the output voltage at the regulation voltage. In the Fig. 2 circuit, however, the output voltage may not be divided down to control the regulator because the output voltage is negative, but the control circuit regulates the voltage at the FB pin to +1.23 V.
Also, increasing inductor current results in a more negative output voltage, so feeding a divided version of the output voltage would cause positive feedback, and thus an unstable regulation circuit. Instead, an operational amplifier used in an inverting configuration provides level shifting and polarity inversion, thus presenting a ratiometric version of the output voltage at FB and allowing proper control of the output voltage.
A general-purpose op amp — such as the AD8541 shown in Fig. 2 — is sufficient for this application. This amplifier should have a gain bandwidth product above 100 kHz and be able to source a few hundred microamperes of current. Note also that the op amp should support positive single-supply operation with a common-mode input voltage range that includes ground. The ratio of the feedback resistors sets the ratio of the absolute value of the output voltage to the voltage reference of the boost converter. Thus in Fig. 2, to regulate an output voltage of -12 V, the resistor values are R1 = 100 kΩ and R2 = 10 kΩ. The charge-pump capacitor C1 (typically 1 µF) should be large enough to hold the charge that needs to be drawn from the load during a single switching cycle.
While the above solutions show that a boost converter can be used to generate either a large positive or a large negative voltage rail, it is more cost-effective to use the same boost converter to generate both positive and negative voltage rails. The challenge in doing this is that the boost converter can only regulate the output voltage of one rail. Thus, the boost converter regulates one of the voltage rails (positive or negative) while the other rail is post-regulated.
The voltage rail that is being regulated by the boost converter must have a higher magnitude than the other rail. This is the positive rail in most LCD applications. A simple circuit is shown in Fig. 3 where the boost converter is regulating the positive voltage rail (+12 V) while the negative rail (-6 V) is generated by a linear regulator, such as Analog Devices' ADP3331, which post-regulates the unregulated charge-pump output.
When the ADP1611 switch turns off, L1 dumps current through D
Thus, if the voltage across C
This topology offers a simple, cost-effective solution to generate large positive and negative voltages using just a single boost converter, a conventional, low-cost positive supply LDO and a few diodes. It does have a few limitations: the magnitude of the positive rail must be greater than that of the negative rail, and the boost converter must be capable of supplying the total maximum load current of both rails.

