Negative Supply Uses Positive Hysteretic Regulator
Aug 1, 2007 12:00 PM
By Ron Crews, Principal Applications Engineer, Medium and High Power Management Group, National Semi
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Frequently, the use of a hysteretic regulator is preferred because of its simplicity of use and wide input-voltage range. For example, National Semiconductor's LM5007 is a constant-on-time variation of the hysteretic topology, but offers a nearly constant frequency of operation. Most of the standard hysteretic regulators are set up for positive-buck applications, with little support for negative-output requirements.
The circuit in the figure illustrates the implementation of a negative buck constant-on-time IC. The circuit is built around the LM5007 constant-on-time regulator, without much additional complication over the positive-buck implementation, for which the LM5007 was designed. The switching output of this device is configured to source current directly into the inductor, which is standard for a positive-buck implementation. In this application, transistor Q3 inverts the drive output of U1. Therefore, when this output is high, Q1 now sinks inductor current to -V
A hysteretic regulator depends on the ripple voltage on the output (caused in this circuit by the ripple current through R6 and the ESR of C2) to trigger the next on-time cycle. In the case of a negative regulator, this ripple is referenced to -V
There must be at least 50 mV of ripple on the 2.5-V signal applied to the FB pin of U1 to ensure reliable triggering. The purpose of R6 is to add resistance to the ESR of C2, which increases the ripple component on the output. R6 is listed in the schematic as 1 Ω, but this should be adjusted to tune in the required ripple voltage. The LM5007 datasheet includes some additional circuitry to allow operation at reduced ripple. Those techniques also apply to this negative converter implementation.
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Since U1 is now driving a PMOS FET (Q3), whose source is tied to U1's V
The value of -V
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