Overpower Compensation for Current-Mode Supplies
Sep 1, 2004 12:00 PM
By Christophe Basso, Application Manager, ON Semiconductor, Toulouse, France
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A current-mode power supply works by observing the peak current circulating in an inductance. By adjusting the peak current setpoint at which the power switch turns off, the feedback loop is able to regulate the power flow to a given load. However, situations exist where the loop asks for the maximum output power. This can occur during startup, or when the converter experiences an overload or short circuit. Unfortunately, the internal circuitry inside a pulse width modulation (PWM) controller includes several cascaded logic gates that hamper the controller's reaction time.
Fig.1 shows a simplified arrangement for the NCP1200 fixed-frequency controller from ON Semiconductor. When the voltage developed across R
Typically, this propagation delay t
For example, a Q
In normal operation, when the power supply regulates, this drawback is permanently compensated by the loop, which slightly lowers the feedback voltage since I
The on-time inductor slope S
I
To see the effect of the propagation delay, let's take the example of a flyback converter designed to operate from a universal input of 85 Vac to 265 Vac with the following operating conditions:
- Low line rectified voltage (Vin DC
LL ) = 120 V - High line rectified voltage (Vin DC
HL ) = 374 V - Efficiency (η) = 85% at low line and 87% at high line
- Primary inductance (L
p ) = 180 µH - Primary sense resistor (R
sense ) = 0.33 Ω - Switching frequency (F
sw ) = 60 kHz - Controller propagation delay, worse case (t
p ) = 160ns - Gate resistor = 22 Ω
- MOSFET gate charge (Q
g ) = 100 nC - Total propagation delay including R
gate CQg network tptot = 160 + 200 = 360 ns - Maximum set point = 1 V.
In a flyback converter operating in discontinuous conduction mode (DCM), transmitted output power is calculated as:
P
In overload, just before the controller internal protection trips, the maximum current set point imposes a 1-V level over R
3 + 360 ns × 120 V/ 180 µH = 3.24 A at 120 Vdc (Eq. 4)
and
3 + 360 ns × 374 V / 180 µH = 3.75 A at 374 Vdc (Eq. 5)
We can therefore calculate the delivered power at low line and high line, assuming the power supply stays in DCM at low line:
P
P
There is an almost 20-W power difference between the two levels or a 37% increase in power capability at high line. In some applications, where the output current must absolutely stay below a safe value, this isn't acceptable.
To circumvent this problem, we could think of reducing the current clamp from its maximum value at low line (1 V in our example) down to another value, such as 0.85 V at high line. However, we don't have access to this clamp, so to achieve this effect we would need to sense the bulk voltage via a dedicated pin on the controller.
A more practical alternative is overpower protection, OPP. It consists of offsetting the voltage sense from its floor point, since we cannot touch the ceiling point. Fig. 3a illustrates how it works. This method requires that equation 7 equal what the power supply delivers at low line:
0.5 × 0.87 × Ip
where the slight difference from the previous result is due to the efficiency variation between high and low line. From equation 5, Ip
Because the controller deals with voltages, 2.45 A over a 0.33-Ω resistor means 808 mV. From the maximum 1-V set point, we need to create an offset of 1 - 808 mV = 191.5 mV at V
(374-0.1915) / (0.1915 / (0.33 + 1k) ) = 1.95 MΩ.
At low line, the remaining offset will be:
120 × (1000.33 / (1000.33 + 1.95 M) ) = 61.5 mV.
The peak current at low line now becomes:
(1 - 61.5 m) / 0.33 + 120 × 360 n/ 180 µ = 3.083 A.
Compared to 3.24 A before compensation, it corresponds to a final power decrease of 10% (P
A mean exists to compensate the propagation delay influence in a current-mode converter. Here, the DCM mode was covered but the analysis still holds in continuous conduction mode (CCM), where the power transfer becomes:
Pout = η × 0.5 × L
and where I
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